of real numbers is defined as a if, for all indices , the following inequality holds:
∑i=1k+1fi2=(∑i=1kfi2)+fk+12sum from i equals 1 to k plus 1 of f sub i squared equals open paren sum from i equals 1 to k of f sub i squared close paren plus f sub k plus 1 end-sub squared Substitute the inductive hypothesis: stefani_problem_stefani_problem
∑i=1nfi2=fnfn+1sum from i equals 1 to n of f sub i squared equals f sub n f sub n plus 1 end-sub Step-by-Step Induction Proof .The base case holds. Inductive Step: Assume the formula holds for . We must show it holds for of real numbers is defined as a if,
This property is closely related to the , which is often used to optimize dynamic programming algorithms from 2. Fundamental Proof Techniques Fundamental Proof Techniques A[i
A[i,j]+A[k,l]≤A[i,l]+A[k,j]cap A open bracket i comma j close bracket plus cap A open bracket k comma l close bracket is less than or equal to cap A open bracket i comma l close bracket plus cap A open bracket k comma j close bracket
In the De Stefani curriculum, problems are designed to test five fundamental proof techniques: