Problems:... — Mechanics Of Materials - Formulas And

σ=PAsigma equals the fraction with numerator cap P and denominator cap A end-fraction The deformation per unit length.

δ=160,00080,000,000=0.002 m or 2 mmdelta equals the fraction with numerator 160 comma 000 and denominator 80 comma 000 comma 000 end-fraction equals 0.002 m or 2 mm Practice Problem: Bending Stress A rectangular beam ( ) experiences a maximum bending moment of . Determine the maximum bending stress. Solution: Find : Find : Apply Formula: Result: Mechanics of Materials - Formulas and Problems:...

τ=TcJtau equals the fraction with numerator cap T c and denominator cap J end-fraction Measured in radians. σ=PAsigma equals the fraction with numerator cap P

τ=VQIttau equals the fraction with numerator cap V cap Q and denominator cap I t end-fraction (Where is the first moment of area and is the thickness at the point of interest). Practice Problem: Axial Loading A steel rod ( ) is 2 meters long and has a cross-sectional area of . If it is subjected to a tensile load of , calculate the total elongation. Solution: Identify Givens: Apply Formula: Calculate: Solution: Find : Find : Apply Formula: Result:

σ=Eϵwhere E is Young′s Modulussigma equals cap E epsilon space where cap E is Young prime s Modulus